-50x^2+1000x-3750=0

Solution for -50x^2+1000x-3750=0 equation:

-50x^2+1000x-3750=0

a = -50; b = 1000; c = -3750;
Δ = b2-4ac
Δ = 10002-4·(-50)·(-3750)
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1000)-500}{2*-50}=\frac{-1500}{-100}
=+15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1000)+500}{2*-50}=\frac{-500}{-100}
=+5
$